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Example Problem | |||||||||||||||||||||||||||||||||||
| Short Method Chain Pull Calculation | ||||||||||||||||||||||||||||||||||||
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Assume that after working out Step No. 1 thru Step No. 8, the following information is established:
In checking Table 5, it is seen that a 4-inch system can be safely used for a 211.6 lb. trolley load. Table 3 indicates that No. 458 chain with 4-inch Trolleys on 24-inch centers weighs 7.1 lbs. per foot of conveyor. Chain pull can now be calculated as described in Step No. 9. 316'-0" No. 458 chain with 4-inch trolleys
Using friction factor of 2-1/2% as indicated in Table 2:
With both total chain pull and maximum conveyor speed calculated, the drive horsepower can be determined from the formula given in Step No. 9: Drive horsepower: 640 lbs. x 20 FPM / 33000 x 0.70 = 0.55 H.P. The drive selection charts, in the Drive Unit Section, indicate that an Anchor Size 1 caterpillar drive unit has a capacity of 950 lbs. chain pull at 20 FPM. An overhead safety device such as the Anchor Cut-Out, described in another section of this manual, is recommended on conveyor drives. Other types are available. Step No. 5, and Table 6 establish the use of a minimum 10'-0" radius for vertical curves, using X-458 chain with trolleys spaced on 24-inch centers. Checking the procedure referred to in Step No. 11 and Table 8 and Table 9, it will be found that the calculated chain pull of 640 lbs. is well under he allowable chain pull for a 211.6 lb. trolley load with 10'-0" radius vertical curves. Table 7 shows that for 24-inch trolley spacing a 30-inch minimum diameter traction wheel could be used. Use larger size if space permits. Finally, the take-up, guards, safety devices, and expansion joints (if required) should be indicated on the layout to complete the conveyor system. |